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## Homework Statement

Two spaceships A and B are launched from a point X, in opposite directions.

At time t=15 minutes, spaceship A crashes.

The velocity of the spaceships relative to X is 1.3x10⁸m/s.

How far did the collision happen from B, as observed by astronauts on the spaceship?

## Homework Equations

x'=ɣ(x-vt)

x=vt

## The Attempt at a Solution

I've calculated ɣ to be 1.11

The distance from spaceship A to the point X is 1.17x10¹¹m, so the distance from point B to x is also 1.17x10¹¹m.

x'=ɣ(x-vt)

x'=1.11(2*1.17x10¹¹-1.3x10⁸(60*15))

x'=1.30x10¹¹m

So the distance is 2(1.17x10¹¹)+1.30x10¹¹=3.64x10¹¹m.

I am probably using the equations incorrectly, so if anyone could help me out, it will be appreciated.